Solve it

Solve it

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(A+B)^2

What are we doing here?

Correct

math. no prize. sorry.

I'm afraid your answer is incorrect. The variables A and B are undefined according to the problem.

The correct answer is (a+b)x(a+b)

(A+B)² is the exact same shit as (A+B) x (A+B) so it really doesn't matter

lol

that's not an equation, thats an expression.

90 and 1/5

solve this, faggot.

A lunch box's purpose is to store lunch in the box.
We as living beings consume lunch, not store it in our bodies.

1/15

NOW WE'RE GETTING SERIOUS FAGGOTS

you fucker

...

is log^2(x) the same as 2log(x)?

No.

no solution

Try x=1/10, and if it works find another solution.

Wolfram can't solve it yet I think, but a high school student can. This ain't no game, user. This is real life.

i put it in my ti84 nigger. it doesnt cross the x axis

Did you use base 10 logs? Check again kike

check your algebra faggot

Dubs confirm.

for some reason my ti84 and an online calculator are giving different graphs but 1/10 works on both. im retarded i guess

10^(-3)*(10^(-1))^log(10^(-1))+10^(-1)*((log(10^(-1)))^2-2*log(10^(-1)))-(10^(-1))^2-3*10^(-1)=(1/1000)*10+(1/10)*(1-2*(-1))-(1/100)-(3/10)=0

you right nigga

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bump. im bored give me math

sit down, u fucks

what is 0/0 Holla Forums?

Let's throw away our current numerical system for something better goys.

en.wikipedia.org/wiki/Bijective_numeration

The radius of a circle is 45cm. What is the circumference?

If a barrel holds 160 litres and loses 15% every week through evaporation and a new barrel is introduced every week, evaporating at the same rate. How much liquid is left after 20 weeks?

90(pi)

Is that 15% of the initial volume that is lost or 15% of the remaining volume being lost?

if 15% managed to evaporate out of 100%, im pretty sure 15% of 100%, not remaining

Hardy-(((Weinberg))) expression for allele and genotype frequencies in a population.

15% of what remains. Its a geometric series problem.

160 x (0.85)^20 + 160 x (0.85)^19 +…

log^2(x) = (log(x))^2
2log(x) = log(x^2)

Do these look like the same to you?

log(x)^2 is the same as 2log(x)