Woah… powerful…

Woah… powerful…

Other urls found in this thread:

wolframalpha.com/input/?i=x/[y+z] + y/[x+z] + z/[x+y] = 4
twitter.com/SFWRedditGifs

you can't multiply a letter retard, numbers and the alphabet are different things.

Woah… powerful…

Pierced your sisters buns

Should have stayed in school and learnt variable equations nigger

It's bonded your sister's meat.

it's silenty pounded

...

Its goldfingered your sister's meatloaf

Doggiestyled your fat cow of a sister.

my IQ is 198, I don't need school

U fookin wat m8?

Your digits only say 172 pleb. Look at my naturally higher digits

I bet you can't solve this genious

solved ;)

Whoever made that pic is retarded.

I bet you couldn't solve it hahaha idiot!

15+15 if the author's a smartass and he's like "I DIDN'T SAY YOU HAVE TO FILL ALL THE BOXES LOL".
Otherwise impossible since 30's an even number and these are all odd numbers, so odd + odd + odd = odd.

wrong

Wrong.

They're all odd numbers.

Obviously 3×5 (in 1 box) + 15 + empty box = 30.

can't repeat

You can repeat numbers.
Instead of pulling the x sign out of your ass you could make it simpler and make it 15+15, but that's leave one empty box so this is a troll

i bet you can't even

sub 80 IQ retarts spotted.

trips confirm, one true solution.

Solve this faggots

My post digits are higher meaning I am superior to thou

Flawed test

life is not one of your video games kid 😫

And my life isn't like yours bucko

i know, i'm not a virgin no life drumf supporter nazi nerd 😏

C
Breddy easy goy.

Noice try, but I am the real Drumpf poster here

Choosing C is a 1/4 chance, so it is 25%

But you will never have a 0% chance or 50% chance, so the answer is 50% that you will pick 25%. Get gud faggot

We need an answer bud

B

Incorrect, picking C is a 1 in a 4 chance, not a 2/4

The correct answer is 25%, but there are two of those, so either A or D are fine. That makes half the answers, to it's 50%

I-I…Uh…

The point of it is to coax you into a snafu, surely there's some rule against having the same option twice.

I figured it out. Indeed, all answers are wrong, it's impossible. Not because of a rule against having the same option twice though.

If we follow this logic , we arrive to the conclusion that 50% is correct.
However, if 50% is the right answer and 50% is 1 of the 4 possible answers, we got to the same logic problem as before when we just started. It's cyclical logic or whatever the fuck it's called, it'll never stop.
You can't even say the correct answer is C (0%) due to the fact that there are no possible answers because 0% is in itself one of the answers and you'll get the same logical problem. So it's unsolvable.

...

Apple = 4, Banana = -1, Pineapple = 11

...

do the math, you will see i'm right

(4/10) + (-1/15) + (11/3) = 4

drumphcuck btfo

For the purposes of this, I'll assign apple X, Banana Y, and Pineapple Z.

[X/(Y+Z)] + [Y/(X+Z)] + [Z/(X+Y)] = (4/1)

[(X+Y+Z)/(2X+2Y+2Z)] = (4/1)

[(X+Y+Z)/2(X+Y+Z)] = (4/1)

1/2 =/= 4/1

Failed highschool math or good troll.

Z≈0.381571 (36 X^3 + 153 X^2 Y + 1.73205 sqrt(-432 X^6 - 1080 X^5 Y + 171 X^4 Y^2 + 1642 X^3 Y^3 + 171 X^2 Y^4 - 1080 X Y^5 - 432 Y^6) + 153 X Y^2 + 36 Y^3)^(1/3) - (0.291193 (-18 X^2 - 33 X Y - 18 Y^2))/(36 X^3 + 153 X^2 Y + 1.73205 sqrt(-432 X^6 - 1080 X^5 Y + 171 X^4 Y^2 + 1642 X^3 Y^3 + 171 X^2 Y^4 - 1080 X Y^5 - 432 Y^6) + 153 X Y^2 + 36 Y^3)^(1/3) + 0.333333 (3 X + 3 Y), Y X^2 + (0.333333 (3 X + 3 Y) + 0.381571 (36 X^3 + 153 Y X^2 + 153 Y^2 X + 36 Y^3 + 1.73205 sqrt(-432 X^6 - 1080 Y X^5 + 171 Y^2 X^4 + 1642 Y^3 X^3 + 171 Y^4 X^2 - 1080 Y^5 X - 432 Y^6))^(1/3) - (0.291193 (-18 X^2 - 33 Y X - 18 Y^2))/(36 X^3 + 153 Y X^2 + 153 Y^2 X + 36 Y^3 + 1.73205 sqrt(-432 X^6 - 1080 Y X^5 + 171 Y^2 X^4 + 1642 Y^3 X^3 + 171 Y^4 X^2 - 1080 Y^5 X - 432 Y^6))^(1/3)) X^2 + Y^2 X + (0.333333 (3 X + 3 Y) + 0.381571 (36 X^3 + 153 Y X^2 + 153 Y^2 X + 36 Y^3 + 1.73205 sqrt(-432 X^6 - 1080 Y X^5 + 171 Y^2 X^4 + 1642 Y^3 X^3 + 171 Y^4 X^2 - 1080 Y^5 X - 432 Y^6))^(1/3) - (0.291193 (-18 X^2 - 33 Y X - 18 Y^2))/(36 X^3 + 153 Y X^2 + 153 Y^2 X + 36 Y^3 + 1.73205 sqrt(-432 X^6 - 1080 Y X^5 + 171 Y^2 X^4 + 1642 Y^3 X^3 + 171 Y^4 X^2 - 1080 Y^5 X - 432 Y^6))^(1/3))^2 X + 2 Y (0.333333 (3 X + 3 Y) + 0.381571 (36 X^3 + 153 Y X^2 + 153 Y^2 X + 36 Y^3 + 1.73205 sqrt(-432 X^6 - 1080 Y X^5 + 171 Y^2 X^4 + 1642 Y^3 X^3 + 171 Y^4 X^2 - 1080 Y^5 X - 432 Y^6))^(1/3) - (0.291193 (-18 X^2 - 33 Y X - 18 Y^2))/(36 X^3 + 153 Y X^2 + 153 Y^2 X + 36 Y^3 + 1.73205 sqrt(-432 X^6 - 1080 Y X^5 + 171 Y^2 X^4 + 1642 Y^3 X^3 + 171 Y^4 X^2 - 1080 Y^5 X - 432 Y^6))^(1/3)) X + Y (0.333333 (3 X + 3 Y) + 0.381571 (36 X^3 + 153 Y X^2 + 153 Y^2 X + 36 Y^3 + 1.73205 sqrt(-432 X^6 - 1080 Y X^5 + 171 Y^2 X^4 + 1642 Y^3 X^3 + 171 Y^4 X^2 - 1080 Y^5 X - 432 Y^6))^(1/3) - (0.291193 (-18 X^2 - 33 Y X - 18 Y^2))/(36 X^3 + 153 Y X^2 + 153 Y^2 X + 36 Y^3 + 1.73205 sqrt(-432 X^6 - 1080 Y X^5 + 171 Y^2 X^4 + 1642 Y^3 X^3 + 171 Y^4 X^2 - 1080 Y^5 X - 432 Y^6))^(1/3))^2 + Y^2 (0.333333 (3 X + 3 Y) + 0.381571 (36 X^3 + 153 Y X^2 + 153 Y^2 X + 36 Y^3 + 1.73205 sqrt(-432 X^6 - 1080 Y X^5 + 171 Y^2 X^4 + 1642 Y^3 X^3 + 171 Y^4 X^2 - 1080 Y^5 X - 432 Y^6))^(1/3) - (0.291193 (-18 X^2 - 33 Y X - 18 Y^2))/(36 X^3 + 153 Y X^2 + 153 Y^2 X + 36 Y^3 + 1.73205 sqrt(-432 X^6 - 1080 Y X^5 + 171 Y^2 X^4 + 1642 Y^3 X^3 + 171 Y^4 X^2 - 1080 Y^5 X - 432 Y^6))^(1/3))!=0

Apple = 154476802108746166441951315019919837485664325669565431700026634898253202035277999

Banana = 36875131794129999827197811565225474825492979968971970996283137471637224634055579

Pineapple = 4373612677928697257861252602371390152816537558161613618621437993378423467772036

This is the only right answer. If you keep this in the back of your mind for every test you take, you will always choose the correct answer.

Yeah really nice equation there, really handy.

wolframalpha.com/input/?i=x/[y+z] + y/[x+z] + z/[x+y] = 4

How did you solve it?
Did you assign random values to two of the fruits and then solved for the remaining fruit?

I'll admit it, I couldn't solve it.

...

I don't know why the guy in the middle is. Man I feel bad since I can't solve any of these in the thread. What the heck.

Stanley Kubrick

Q from star strek

OK, no idea how the first guy managed to get all three numbers to be integers.
I assigned arbitrary values to two of the numbers and solved for the other number. Got:
Apple = 4
Banana = 4
Pineapple = 30.1245154965971 or -2.1245154965970983

Obviously this shit has infinite solutions . I learned a formula to obtain the relationship between variables when there are infinite solutions but I don't remember it.

This is the only correct solution posted so far. It's the smallest correct solution.

+15+15=30

There's no reason to make it so complicated. You have two free variables, so you can arbitrarily chose their values. For simplicity, we'll set
and reduce the equation to a 1-variable problem:
Since
We have
Thus, by setting
We fulfill the condition
and, therefore, solve the equation.

...

It's Wolfram Alpha, what do you think is going to happen

racist math virus

W isn't a veriable it's a unit. Should've taken igh school physics retard. You take music instead or are you full-on scum?

It's actually a upside-down M

all Ws are that idiot

/trannypol/s can't solve this with only pen and paper tbh logarithm is in base 10

solved ;)

Post your full solution nigger faggot

Where did this come from?

REVERSE IMAGE SEARCH IT

FIRST POST HAS BOTH CORRECT ANSWERS AND AN EXPLANATION

...

...

It seems that "95% of people can't solve this" should've been "99,5% of people" instead.

He wasn't alone.

This is a really good one. It took me a minute to figure it out but I got it.

lake pedo paw rats faggotry blue eyelash mars?

...

pier onion foot mouse messenger ocean iris alien

...

its possible if your not an idiot.

Proof:

thats not how letters work fucktard

Doctor PawRat I'm CIA?

You got that backwards, birdbrain .

I apologize if I was unclear.

Since
Multiplying (sqrt(3)+2) with 5 gives 0:
From (1) and (2) we get

Yes, I see that. I'm asking why (sqrt(3)+2) in particular. Anything multiplied by zero is going to be zero, so it could've been any number. For example, you could've said
Unless I'm missing something.

It does not necesarily have to be
For example,
so
is another solution.

With regards to your example:
and since
it's not a possible solution.